Base | Representation |
---|---|
bin | 1011001111000011011100… |
… | …0110100101100000000001 |
3 | 1121201221220021001120112221 |
4 | 2303300313012211200001 |
5 | 3104343424101313031 |
6 | 42135001020251041 |
7 | 2413331030012101 |
oct | 263606706454001 |
9 | 47657807046487 |
10 | 12353250416641 |
11 | 3a32a908a22a2 |
12 | 14761866a0a81 |
13 | 6b7ba27cc964 |
14 | 309c87001201 |
15 | 16650a4d0a11 |
hex | b3c371a5801 |
12353250416641 has 4 divisors (see below), whose sum is σ = 12378006430000. Its totient is φ = 12328494403284.
The previous prime is 12353250416629. The next prime is 12353250416677. The reversal of 12353250416641 is 14661405235321.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12353250416641 - 213 = 12353250408449 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12353250416341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12378005931 + ... + 12378006928.
It is an arithmetic number, because the mean of its divisors is an integer number (3094501607500).
Almost surely, 212353250416641 is an apocalyptic number.
It is an amenable number.
12353250416641 is a deficient number, since it is larger than the sum of its proper divisors (24756013359).
12353250416641 is an equidigital number, since it uses as much as digits as its factorization.
12353250416641 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24756013358.
The product of its (nonzero) digits is 518400, while the sum is 43.
The spelling of 12353250416641 in words is "twelve trillion, three hundred fifty-three billion, two hundred fifty million, four hundred sixteen thousand, six hundred forty-one".
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