Base | Representation |
---|---|
bin | 10001111111100110111… |
… | …100100100000101011001 |
3 | 11101012200220211002101101 |
4 | 101333212330210011121 |
5 | 130224403221000243 |
6 | 2344015410351401 |
7 | 155223241463566 |
oct | 21774674440531 |
9 | 4335626732341 |
10 | 1236530250073 |
11 | 4374560a9708 |
12 | 17b79358b561 |
13 | 8c7b18626b1 |
14 | 43bc3d6d86d |
15 | 22271c8d54d |
hex | 11fe6f24159 |
1236530250073 has 4 divisors (see below), whose sum is σ = 1276418322688. Its totient is φ = 1196642177460.
The previous prime is 1236530250023. The next prime is 1236530250091. The reversal of 1236530250073 is 3700520356321.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1236530250073 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1236530250023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19944036261 + ... + 19944036322.
It is an arithmetic number, because the mean of its divisors is an integer number (319104580672).
Almost surely, 21236530250073 is an apocalyptic number.
It is an amenable number.
1236530250073 is a deficient number, since it is larger than the sum of its proper divisors (39888072615).
1236530250073 is an equidigital number, since it uses as much as digits as its factorization.
1236530250073 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39888072614.
The product of its (nonzero) digits is 113400, while the sum is 37.
The spelling of 1236530250073 in words is "one trillion, two hundred thirty-six billion, five hundred thirty million, two hundred fifty thousand, seventy-three".
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