123807918476755 has 4 divisors (see below), whose sum is σ = 148569502172112. Its totient is φ = 99046334781400.

The previous prime is 123807918476731. The next prime is 123807918476791. The reversal of 123807918476755 is 557674819708321.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2^k-123807918476755 is a prime.

It is a super-3 number, since 3×123807918476755³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12380791847671 + ... + 12380791847680.

It is an arithmetic number, because the mean of its divisors is an integer number (37142375543028).

It is a 2-persistent number, because it is pandigital, and so is 2⋅123807918476755 = 247615836953510, but 3⋅123807918476755 = 371423755430265 is not.

Almost surely, 2^{123807918476755} is an apocalyptic number.

123807918476755 is a deficient number, since it is larger than the sum of its proper divisors (24761583695357).

123807918476755 is an equidigital number, since it uses as much as digits as its factorization.

123807918476755 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24761583695356.

The product of its (nonzero) digits is 711244800, while the sum is 73.

The spelling of 123807918476755 in words is "one hundred twenty-three trillion, eight hundred seven billion, nine hundred eighteen million, four hundred seventy-six thousand, seven hundred fifty-five".