1240113121 has 4 divisors (see below), whose sum is σ = 1335506452. Its totient is φ = 1144719792.

The previous prime is 1240113107. The next prime is 1240113131. The reversal of 1240113121 is 1213110421.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 811623121 + 428490000 = 28489^2 + 20700^2 .

It is a cyclic number.

It is not a de Polignac number, because 1240113121 - 2²³ = 1231724513 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1240113095 and 1240113104.

It is not an unprimeable number, because it can be changed into a prime (1240113131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47696646 + ... + 47696671.

It is an arithmetic number, because the mean of its divisors is an integer number (333876613).

Almost surely, 2^1240113121 is an apocalyptic number.

It is an amenable number.

1240113121 is a deficient number, since it is larger than the sum of its proper divisors (95393331).

1240113121 is an equidigital number, since it uses as much as digits as its factorization.

1240113121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 95393330.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 1240113121 is about 35215.2398969537. The cubic root of 1240113121 is about 1074.3697393729.

Adding to 1240113121 its reverse (1213110421), we get a palindrome (2453223542).

The spelling of 1240113121 in words is "one billion, two hundred forty million, one hundred thirteen thousand, one hundred twenty-one".