124012113 has 8 divisors (see below), whose sum is σ = 172538688. Its totient is φ = 79080144.

The previous prime is 124012111. The next prime is 124012139. The reversal of 124012113 is 311210421.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 124012113 - 2¹ = 124012111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 124012092 and 124012101.

It is not an unprimeable number, because it can be changed into a prime (124012111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 898570 + ... + 898707.

It is an arithmetic number, because the mean of its divisors is an integer number (21567336).

Almost surely, 2^124012113 is an apocalyptic number.

It is an amenable number.

124012113 is a deficient number, since it is larger than the sum of its proper divisors (48526575).

124012113 is a wasteful number, since it uses less digits than its factorization.

124012113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1797303.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 124012113 is about 11136.0726021340. The cubic root of 124012113 is about 498.6793320771.

Adding to 124012113 its reverse (311210421), we get a palindrome (435222534).

The spelling of 124012113 in words is "one hundred twenty-four million, twelve thousand, one hundred thirteen".