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12401215403 = 171395248081
BaseRepresentation
bin10111000110010101…
…11000011110101011
31012000021002000102012
423203022320132223
5200344202343103
65410321030135
7616212406643
oct134312703653
935007060365
1012401215403
115294187755
1224a118534b
1312283103a5
1485901b523
154c8ac42d8
hex2e32b87ab

12401215403 has 8 divisors (see below), whose sum is σ = 13225166640. Its totient is φ = 11587760640.

The previous prime is 12401215349. The next prime is 12401215423. The reversal of 12401215403 is 30451210421.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12401215403 - 28 = 12401215147 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12401215423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2621678 + ... + 2626403.

It is an arithmetic number, because the mean of its divisors is an integer number (1653145830).

Almost surely, 212401215403 is an apocalyptic number.

12401215403 is a deficient number, since it is larger than the sum of its proper divisors (823951237).

12401215403 is a wasteful number, since it uses less digits than its factorization.

12401215403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5248237.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 12401215403 its reverse (30451210421), we get a palindrome (42852425824).

The spelling of 12401215403 in words is "twelve billion, four hundred one million, two hundred fifteen thousand, four hundred three".

Divisors: 1 17 139 2363 5248081 89217377 729483259 12401215403