124013001323 has 4 divisors (see below), whose sum is σ = 124655555928. Its totient is φ = 123370446720.

The previous prime is 124013001319. The next prime is 124013001377. The reversal of 124013001323 is 323100310421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 124013001323 - 2² = 124013001319 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 124013001295 and 124013001304.

It is not an unprimeable number, because it can be changed into a prime (124013001523) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 321277013 + ... + 321277398.

It is an arithmetic number, because the mean of its divisors is an integer number (31163888982).

Almost surely, 2^124013001323 is an apocalyptic number.

124013001323 is a deficient number, since it is larger than the sum of its proper divisors (642554605).

124013001323 is an equidigital number, since it uses as much as digits as its factorization.

124013001323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 642554604.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 124013001323 its reverse (323100310421), we get a palindrome (447113311744).

The spelling of 124013001323 in words is "one hundred twenty-four billion, thirteen million, one thousand, three hundred twenty-three".