Search a number
-
+
12401331 = 34133777
BaseRepresentation
bin101111010011…
…101010110011
3212100001102120
4233103222303
511133320311
61121445323
7210260325
oct57235263
925301376
1012401331
117000338
1241a0843
132752887
14190b615
15114e706
hexbd3ab3

12401331 has 4 divisors (see below), whose sum is σ = 16535112. Its totient is φ = 8267552.

The previous prime is 12401317. The next prime is 12401351. The reversal of 12401331 is 13310421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12401331 - 26 = 12401267 is a prime.

It is a super-2 number, since 2×124013312 = 307586021143122, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12401331.

It is not an unprimeable number, because it can be changed into a prime (12401351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2066886 + ... + 2066891.

It is an arithmetic number, because the mean of its divisors is an integer number (4133778).

Almost surely, 212401331 is an apocalyptic number.

12401331 is a deficient number, since it is larger than the sum of its proper divisors (4133781).

12401331 is an equidigital number, since it uses as much as digits as its factorization.

12401331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4133780.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 12401331 is about 3521.5523565610. The cubic root of 12401331 is about 231.4671866564.

Adding to 12401331 its reverse (13310421), we get a palindrome (25711752).

The spelling of 12401331 in words is "twelve million, four hundred one thousand, three hundred thirty-one".

Divisors: 1 3 4133777 12401331