12401343000001 has 4 divisors (see below), whose sum is σ = 12940531826112. Its totient is φ = 11862154173892.

The previous prime is 12401342999993. The next prime is 12401343000023. The reversal of 12401343000001 is 10000034310421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12401343000001 - 2³ = 12401342999993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12401343000071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 269594413021 + ... + 269594413066.

It is an arithmetic number, because the mean of its divisors is an integer number (3235132956528).

Almost surely, 2^{12401343000001} is an apocalyptic number.

It is an amenable number.

12401343000001 is a deficient number, since it is larger than the sum of its proper divisors (539188826111).

12401343000001 is an equidigital number, since it uses as much as digits as its factorization.

12401343000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 539188826110.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 12401343000001 its reverse (10000034310421), we get a palindrome (22401377310422).

The spelling of 12401343000001 in words is "twelve trillion, four hundred one billion, three hundred forty-three million, one", and thus it is an aban number.