12402013033 has 4 divisors (see below), whose sum is σ = 12402793728. Its totient is φ = 12401232340.

The previous prime is 12402013021. The next prime is 12402013037. The reversal of 12402013033 is 33031020421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12402013033 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12402013033.

It is not an unprimeable number, because it can be changed into a prime (12402013037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 366013 + ... + 398458.

It is an arithmetic number, because the mean of its divisors is an integer number (3100698432).

Almost surely, 2^12402013033 is an apocalyptic number.

It is an amenable number.

12402013033 is a deficient number, since it is larger than the sum of its proper divisors (780695).

12402013033 is an equidigital number, since it uses as much as digits as its factorization.

12402013033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 780694.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 12402013033 its reverse (33031020421), we get a palindrome (45433033454).

The spelling of 12402013033 in words is "twelve billion, four hundred two million, thirteen thousand, thirty-three".