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12402304307 = 41302495227
BaseRepresentation
bin10111000110011110…
…00010010100110011
31012000100010100002222
423203033002110303
5200344442214212
65410400231255
7616224563411
oct134317022463
935010110088
1012402304307
115294860878
1224a160b52b
131228601c03
148592222b1
154c8c3bc72
hex2e33c2533

12402304307 has 4 divisors (see below), whose sum is σ = 12704799576. Its totient is φ = 12099809040.

The previous prime is 12402304297. The next prime is 12402304309. The reversal of 12402304307 is 70340320421.

12402304307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12402304307 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12402304309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 151247573 + ... + 151247654.

It is an arithmetic number, because the mean of its divisors is an integer number (3176199894).

Almost surely, 212402304307 is an apocalyptic number.

12402304307 is a deficient number, since it is larger than the sum of its proper divisors (302495269).

12402304307 is an equidigital number, since it uses as much as digits as its factorization.

12402304307 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 302495268.

The product of its (nonzero) digits is 4032, while the sum is 26.

Adding to 12402304307 its reverse (70340320421), we get a palindrome (82742624728).

The spelling of 12402304307 in words is "twelve billion, four hundred two million, three hundred four thousand, three hundred seven".

Divisors: 1 41 302495227 12402304307