Base | Representation |
---|---|
bin | 10111000110100011… |
… | …10110001101011001 |
3 | 1012000101111202211002 |
4 | 23203101312031121 |
5 | 200400134303423 |
6 | 5410424114345 |
7 | 616234052501 |
oct | 134321661531 |
9 | 35011452732 |
10 | 12403041113 |
11 | 5295214401 |
12 | 24a19059b5 |
13 | 12287cc3a8 |
14 | 859374a01 |
15 | 4c8d35228 |
hex | 2e3476359 |
12403041113 has 4 divisors (see below), whose sum is σ = 12422211840. Its totient is φ = 12383870388.
The previous prime is 12403041089. The next prime is 12403041143. The reversal of 12403041113 is 31114030421.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31114030421 = 179 ⋅173821399.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12403041113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12403041143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9584393 + ... + 9585686.
It is an arithmetic number, because the mean of its divisors is an integer number (3105552960).
Almost surely, 212403041113 is an apocalyptic number.
It is an amenable number.
12403041113 is a deficient number, since it is larger than the sum of its proper divisors (19170727).
12403041113 is an equidigital number, since it uses as much as digits as its factorization.
12403041113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19170726.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 12403041113 its reverse (31114030421), we get a palindrome (43517071534).
The spelling of 12403041113 in words is "twelve billion, four hundred three million, forty-one thousand, one hundred thirteen".
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