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124042033121 = 196528528059
BaseRepresentation
bin111001110000101111…
…0110011011111100001
3102212011200222011112212
41303201132303133201
54013014230024441
6132552323131505
711650606612346
oct1634136633741
9385150864485
10124042033121
1148673548466
1220059513b95
13b90a734b46
14600a0bc7cd
15335ec7eeeb
hex1ce17b37e1

124042033121 has 4 divisors (see below), whose sum is σ = 130570561200. Its totient is φ = 117513505044.

The previous prime is 124042033103. The next prime is 124042033127. The reversal of 124042033121 is 121330240421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 124042033121 - 26 = 124042033057 is a prime.

It is a super-2 number, since 2×1240420331212 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (124042033127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3264264011 + ... + 3264264048.

It is an arithmetic number, because the mean of its divisors is an integer number (32642640300).

Almost surely, 2124042033121 is an apocalyptic number.

It is an amenable number.

124042033121 is a deficient number, since it is larger than the sum of its proper divisors (6528528079).

124042033121 is an equidigital number, since it uses as much as digits as its factorization.

124042033121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6528528078.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 124042033121 its reverse (121330240421), we get a palindrome (245372273542).

The spelling of 124042033121 in words is "one hundred twenty-four billion, forty-two million, thirty-three thousand, one hundred twenty-one".

Divisors: 1 19 6528528059 124042033121