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1240434113 = 5971296117
BaseRepresentation
bin100100111101111…
…1000010111000001
310012110002120201012
41021323320113001
510020022342423
6323030450305
742511341662
oct11173702701
93173076635
101240434113
11587213566
122a7503995
13169cb07a9
14baa57369
1573d76078
hex49ef85c1

1240434113 has 8 divisors (see below), whose sum is σ = 1279229760. Its totient is φ = 1202230960.

The previous prime is 1240434079. The next prime is 1240434127. The reversal of 1240434113 is 3114340421.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1240434113 - 218 = 1240171969 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1240439113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 143870 + ... + 152247.

It is an arithmetic number, because the mean of its divisors is an integer number (159903720).

Almost surely, 21240434113 is an apocalyptic number.

It is an amenable number.

1240434113 is a deficient number, since it is larger than the sum of its proper divisors (38795647).

1240434113 is an equidigital number, since it uses as much as digits as its factorization.

1240434113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 296247.

The product of its (nonzero) digits is 1152, while the sum is 23.

The square root of 1240434113 is about 35219.7971743166. The cubic root of 1240434113 is about 1074.4624283207.

Adding to 1240434113 its reverse (3114340421), we get a palindrome (4354774534).

The spelling of 1240434113 in words is "one billion, two hundred forty million, four hundred thirty-four thousand, one hundred thirteen".

Divisors: 1 59 71 4189 296117 17470903 21024307 1240434113