1240443124233 has 4 divisors (see below), whose sum is σ = 1653924165648. Its totient is φ = 826962082820.

The previous prime is 1240443124189. The next prime is 1240443124259. The reversal of 1240443124233 is 3324213440421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1240443124233 - 2¹⁶ = 1240443058697 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1240443124194 and 1240443124203.

It is not an unprimeable number, because it can be changed into a prime (1240443120233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 206740520703 + ... + 206740520708.

It is an arithmetic number, because the mean of its divisors is an integer number (413481041412).

Almost surely, 2^{1240443124233} is an apocalyptic number.

It is an amenable number.

1240443124233 is a deficient number, since it is larger than the sum of its proper divisors (413481041415).

1240443124233 is an equidigital number, since it uses as much as digits as its factorization.

1240443124233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 413481041414.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 1240443124233 its reverse (3324213440421), we get a palindrome (4564656564654).

The spelling of 1240443124233 in words is "one trillion, two hundred forty billion, four hundred forty-three million, one hundred twenty-four thousand, two hundred thirty-three".