12405114041 has 4 divisors (see below), whose sum is σ = 13058014800. Its totient is φ = 11752213284.

The previous prime is 12405114017. The next prime is 12405114053. The reversal of 12405114041 is 14041150421.

12405114041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14041150421 = 83 ⋅169170487.

It is a cyclic number.

It is not a de Polignac number, because 12405114041 - 2¹⁴ = 12405097657 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12405113998 and 12405114016.

It is not an unprimeable number, because it can be changed into a prime (12405114091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 326450351 + ... + 326450388.

It is an arithmetic number, because the mean of its divisors is an integer number (3264503700).

Almost surely, 2^12405114041 is an apocalyptic number.

It is an amenable number.

12405114041 is a deficient number, since it is larger than the sum of its proper divisors (652900759).

12405114041 is an equidigital number, since it uses as much as digits as its factorization.

12405114041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 652900758.

The product of its (nonzero) digits is 640, while the sum is 23.

Adding to 12405114041 its reverse (14041150421), we get a palindrome (26446264462).

The spelling of 12405114041 in words is "twelve billion, four hundred five million, one hundred fourteen thousand, forty-one".