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1240992410113 = 1418518748563
BaseRepresentation
bin10010000011110000111…
…010010110101000000001
311101122012220011022020001
4102003300322112220001
5130313023024110423
62350034250120001
7155441643303541
oct22036072265001
94348186138201
101240992410113
11439335954585
12180619a20001
139004314a891
14440c8829321
15224338a4cad
hex120f0e96a01

1240992410113 has 4 divisors (see below), whose sum is σ = 1241001300528. Its totient is φ = 1240983519700.

The previous prime is 1240992410093. The next prime is 1240992410143. The reversal of 1240992410113 is 3110142990421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1240992410113 - 25 = 1240992410081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1240992410143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4232431 + ... + 4516132.

It is an arithmetic number, because the mean of its divisors is an integer number (310250325132).

Almost surely, 21240992410113 is an apocalyptic number.

It is an amenable number.

1240992410113 is a deficient number, since it is larger than the sum of its proper divisors (8890415).

1240992410113 is an equidigital number, since it uses as much as digits as its factorization.

1240992410113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8890414.

The product of its (nonzero) digits is 15552, while the sum is 37.

The spelling of 1240992410113 in words is "one trillion, two hundred forty billion, nine hundred ninety-two million, four hundred ten thousand, one hundred thirteen".

Divisors: 1 141851 8748563 1240992410113