Base | Representation |
---|---|
bin | 10010000011111110001… |
… | …000001010101101001011 |
3 | 11101122210100101002202011 |
4 | 102003332020022231023 |
5 | 130314001304310430 |
6 | 2350112250320351 |
7 | 155450305033243 |
oct | 22037610125513 |
9 | 4348710332664 |
10 | 1241214135115 |
11 | 43943a025889 |
12 | 1806801290b7 |
13 | 9007a0704c6 |
14 | 4410a064b23 |
15 | 224480a122a |
hex | 120fe20ab4b |
1241214135115 has 4 divisors (see below), whose sum is σ = 1489456962144. Its totient is φ = 992971308088.
The previous prime is 1241214135107. The next prime is 1241214135137. The reversal of 1241214135115 is 5115314121421.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1241214135115 - 23 = 1241214135107 is a prime.
It is a super-2 number, since 2×12412141351152 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 124121413507 + ... + 124121413516.
It is an arithmetic number, because the mean of its divisors is an integer number (372364240536).
Almost surely, 21241214135115 is an apocalyptic number.
1241214135115 is a deficient number, since it is larger than the sum of its proper divisors (248242827029).
1241214135115 is an equidigital number, since it uses as much as digits as its factorization.
1241214135115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 248242827028.
The product of its digits is 4800, while the sum is 31.
Adding to 1241214135115 its reverse (5115314121421), we get a palindrome (6356528256536).
The spelling of 1241214135115 in words is "one trillion, two hundred forty-one billion, two hundred fourteen million, one hundred thirty-five thousand, one hundred fifteen".
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