Base | Representation |
---|---|
bin | 11100001110011110110010… |
… | …111001101001110101111011 |
3 | 121021112201011210101121220022 |
4 | 130032132302321221311323 |
5 | 112232404110422324311 |
6 | 1120005155325321055 |
7 | 35101564600624613 |
oct | 3416366271516573 |
9 | 537481153347808 |
10 | 124140441214331 |
11 | 36611735804863 |
12 | 11b0b2ba70618b |
13 | 5436516329159 |
14 | 229260244da43 |
15 | e5429ee375db |
hex | 70e7b2e69d7b |
124140441214331 has 4 divisors (see below), whose sum is σ = 124369905986064. Its totient is φ = 123910976442600.
The previous prime is 124140441214199. The next prime is 124140441214333. The reversal of 124140441214331 is 133412144041421.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 124140441214331 - 214 = 124140441197947 is a prime.
It is a super-2 number, since 2×1241404412143312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 124140441214291 and 124140441214300.
It is not an unprimeable number, because it can be changed into a prime (124140441214333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114732385055 + ... + 114732386136.
It is an arithmetic number, because the mean of its divisors is an integer number (31092476496516).
Almost surely, 2124140441214331 is an apocalyptic number.
124140441214331 is a deficient number, since it is larger than the sum of its proper divisors (229464771733).
124140441214331 is an equidigital number, since it uses as much as digits as its factorization.
124140441214331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 229464771732.
The product of its (nonzero) digits is 36864, while the sum is 35.
Adding to 124140441214331 its reverse (133412144041421), we get a palindrome (257552585255752).
The spelling of 124140441214331 in words is "one hundred twenty-four trillion, one hundred forty billion, four hundred forty-one million, two hundred fourteen thousand, three hundred thirty-one".
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