Base | Representation |
---|---|
bin | 1011010011000010000111… |
… | …1001011001110011000011 |
3 | 1121222111100122102022222101 |
4 | 2310300201321121303003 |
5 | 3112003431203203120 |
6 | 42230224415451231 |
7 | 2421301114612045 |
oct | 264604171316303 |
9 | 47874318368871 |
10 | 12421614116035 |
11 | 3a59a82379513 |
12 | 1487485526b17 |
13 | 6c1478c417a7 |
14 | 30d2d0593a95 |
15 | 1681ac12190a |
hex | b4c21e59cc3 |
12421614116035 has 4 divisors (see below), whose sum is σ = 14905936939248. Its totient is φ = 9937291292824.
The previous prime is 12421614116029. The next prime is 12421614116039. The reversal of 12421614116035 is 53061141612421.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12421614116035 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12421614115985 and 12421614116003.
It is not an unprimeable number, because it can be changed into a prime (12421614116039) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1242161411599 + ... + 1242161411608.
It is an arithmetic number, because the mean of its divisors is an integer number (3726484234812).
Almost surely, 212421614116035 is an apocalyptic number.
12421614116035 is a deficient number, since it is larger than the sum of its proper divisors (2484322823213).
12421614116035 is an equidigital number, since it uses as much as digits as its factorization.
12421614116035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2484322823212.
The product of its (nonzero) digits is 34560, while the sum is 37.
Adding to 12421614116035 its reverse (53061141612421), we get a palindrome (65482755728456).
The spelling of 12421614116035 in words is "twelve trillion, four hundred twenty-one billion, six hundred fourteen million, one hundred sixteen thousand, thirty-five".
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