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12422025433 = 22754722579
BaseRepresentation
bin10111001000110100…
…10001000011011001
31012001201020021102001
423210122101003121
5200420014303213
65412343041001
7616554321406
oct134432210331
935051207361
1012422025433
1152a4a00624
1224a8140161
13122c71840c
1485bab72ad
154ca8351dd
hex2e46910d9

12422025433 has 4 divisors (see below), whose sum is σ = 12476748240. Its totient is φ = 12367302628.

The previous prime is 12422025367. The next prime is 12422025439. The reversal of 12422025433 is 33452022421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12422025433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12422025439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27361063 + ... + 27361516.

It is an arithmetic number, because the mean of its divisors is an integer number (3119187060).

Almost surely, 212422025433 is an apocalyptic number.

It is an amenable number.

12422025433 is a deficient number, since it is larger than the sum of its proper divisors (54722807).

12422025433 is an equidigital number, since it uses as much as digits as its factorization.

12422025433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54722806.

The product of its (nonzero) digits is 11520, while the sum is 28.

Adding to 12422025433 its reverse (33452022421), we get a palindrome (45874047854).

The spelling of 12422025433 in words is "twelve billion, four hundred twenty-two million, twenty-five thousand, four hundred thirty-three".

Divisors: 1 227 54722579 12422025433