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1243143371 = 3931316241
BaseRepresentation
bin100101000011000…
…1101110011001011
310012122012020010002
41022012031303023
510021221041441
6323204513215
742543354461
oct11206156313
93178166102
101243143371
115887a4018
122a83ab80b
1316a71b9c2
14bb160831
157420db9b
hex4a18dccb

1243143371 has 4 divisors (see below), whose sum is σ = 1243463544. Its totient is φ = 1242823200.

The previous prime is 1243143337. The next prime is 1243143383. The reversal of 1243143371 is 1733413421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1243143371 - 214 = 1243126987 is a prime.

It is a super-2 number, since 2×12431433712 = 3090810881722487282, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1243146371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 154190 + ... + 162051.

It is an arithmetic number, because the mean of its divisors is an integer number (310865886).

Almost surely, 21243143371 is an apocalyptic number.

1243143371 is a deficient number, since it is larger than the sum of its proper divisors (320173).

1243143371 is an equidigital number, since it uses as much as digits as its factorization.

1243143371 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 320172.

The product of its digits is 6048, while the sum is 29.

The square root of 1243143371 is about 35258.2383422655. The cubic root of 1243143371 is about 1075.2441114279.

Adding to 1243143371 its reverse (1733413421), we get a palindrome (2976556792).

The spelling of 1243143371 in words is "one billion, two hundred forty-three million, one hundred forty-three thousand, three hundred seventy-one".

Divisors: 1 3931 316241 1243143371