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12432014125051 = 20036206697017
BaseRepresentation
bin1011010011101000110111…
…0010010010011111111011
31122000111012102212112022111
42310322031302102133323
53112141231104000201
642235104412033151
72422116620334043
oct264721562223773
948014172775274
1012432014125051
113a63429965194
1214894a84627b7
136c2445774691
1430d9d98c0723
151685ba195b51
hexb4e8dc927fb

12432014125051 has 4 divisors (see below), whose sum is σ = 12438220824072. Its totient is φ = 12425807426032.

The previous prime is 12432014125001. The next prime is 12432014125073. The reversal of 12432014125051 is 15052141023421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12432014125051 - 217 = 12432013993979 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12432014125001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3103346506 + ... + 3103350511.

It is an arithmetic number, because the mean of its divisors is an integer number (3109555206018).

Almost surely, 212432014125051 is an apocalyptic number.

12432014125051 is a deficient number, since it is larger than the sum of its proper divisors (6206699021).

12432014125051 is an equidigital number, since it uses as much as digits as its factorization.

12432014125051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6206699020.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 12432014125051 its reverse (15052141023421), we get a palindrome (27484155148472).

The spelling of 12432014125051 in words is "twelve trillion, four hundred thirty-two billion, fourteen million, one hundred twenty-five thousand, fifty-one".

Divisors: 1 2003 6206697017 12432014125051