Base | Representation |
---|---|
bin | 10010000101111010100… |
… | …110101100101110010011 |
3 | 11101212011220000201101210 |
4 | 102011322212230232103 |
5 | 130332240420413210 |
6 | 2351055411431203 |
7 | 155553123665154 |
oct | 22057246545623 |
9 | 4355156021353 |
10 | 1243302513555 |
11 | 43a310946483 |
12 | 180b635b5503 |
13 | 9032091c6ab |
14 | 4426756792b |
15 | 2251b5bee20 |
hex | 1217a9acb93 |
1243302513555 has 8 divisors (see below), whose sum is σ = 1989284021712. Its totient is φ = 663094673888.
The previous prime is 1243302513533. The next prime is 1243302513599. The reversal of 1243302513555 is 5553152033421.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1243302513555 - 29 = 1243302513043 is a prime.
It is a super-2 number, since 2×12433025135552 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41443417104 + ... + 41443417133.
It is an arithmetic number, because the mean of its divisors is an integer number (248660502714).
Almost surely, 21243302513555 is an apocalyptic number.
1243302513555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1243302513555 is a deficient number, since it is larger than the sum of its proper divisors (745981508157).
1243302513555 is an equidigital number, since it uses as much as digits as its factorization.
1243302513555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 82886834245.
The product of its (nonzero) digits is 270000, while the sum is 39.
Adding to 1243302513555 its reverse (5553152033421), we get a palindrome (6796454546976).
The spelling of 1243302513555 in words is "one trillion, two hundred forty-three billion, three hundred two million, five hundred thirteen thousand, five hundred fifty-five".
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