12433155424555 has 4 divisors (see below), whose sum is σ = 14919786509472. Its totient is φ = 9946524339640.

The previous prime is 12433155424537. The next prime is 12433155424561. The reversal of 12433155424555 is 55542455133421.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 12433155424555 - 2⁹ = 12433155424043 is a prime.

It is a super-2 number, since 2×12433155424555² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12433155424499 and 12433155424508.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1243315542451 + ... + 1243315542460.

It is an arithmetic number, because the mean of its divisors is an integer number (3729946627368).

Almost surely, 2^{12433155424555} is an apocalyptic number.

12433155424555 is a deficient number, since it is larger than the sum of its proper divisors (2486631084917).

12433155424555 is an equidigital number, since it uses as much as digits as its factorization.

12433155424555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2486631084916.

The product of its digits is 7200000, while the sum is 49.

The spelling of 12433155424555 in words is "twelve trillion, four hundred thirty-three billion, one hundred fifty-five million, four hundred twenty-four thousand, five hundred fifty-five".