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12434153 = 16677459
BaseRepresentation
bin101111011011…
…101011101001
3212101201110012
4233123223221
511140343103
61122301305
7210455114
oct57335351
925351405
1012434153
117022a66
1241b7835
1327647b4
14191957b
1511592d8
hexbdbae9

12434153 has 4 divisors (see below), whose sum is σ = 12443280. Its totient is φ = 12425028.

The previous prime is 12434143. The next prime is 12434161. The reversal of 12434153 is 35143421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 35143421 = 197178393.

It is a cyclic number.

It is not a de Polignac number, because 12434153 - 24 = 12434137 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (12434143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2063 + ... + 5396.

It is an arithmetic number, because the mean of its divisors is an integer number (3110820).

Almost surely, 212434153 is an apocalyptic number.

It is an amenable number.

12434153 is a deficient number, since it is larger than the sum of its proper divisors (9127).

12434153 is an equidigital number, since it uses as much as digits as its factorization.

12434153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9126.

The product of its digits is 1440, while the sum is 23.

The square root of 12434153 is about 3526.2094379092. The cubic root of 12434153 is about 231.6712110858.

Adding to 12434153 its reverse (35143421), we get a palindrome (47577574).

The spelling of 12434153 in words is "twelve million, four hundred thirty-four thousand, one hundred fifty-three".

Divisors: 1 1667 7459 12434153