12434345401 has 4 divisors (see below), whose sum is σ = 12434637952. Its totient is φ = 12434052852.

The previous prime is 12434345387. The next prime is 12434345437. The reversal of 12434345401 is 10454343421.

12434345401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10454343421 = 773 ⋅13524377.

It is a cyclic number.

It is not a de Polignac number, because 12434345401 - 2¹⁷ = 12434214329 is a prime.

It is a super-2 number, since 2×12434345401² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12434345101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68865 + ... + 172078.

It is an arithmetic number, because the mean of its divisors is an integer number (3108659488).

Almost surely, 2^12434345401 is an apocalyptic number.

It is an amenable number.

12434345401 is a deficient number, since it is larger than the sum of its proper divisors (292551).

12434345401 is an equidigital number, since it uses as much as digits as its factorization.

12434345401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 292550.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 12434345401 its reverse (10454343421), we get a palindrome (22888688822).

It can be divided in two parts, 124343 and 45401, that added together give a square (169744 = 412²).

The spelling of 12434345401 in words is "twelve billion, four hundred thirty-four million, three hundred forty-five thousand, four hundred one".