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12435232513 = 111130475683
BaseRepresentation
bin10111001010011001…
…01001011100000001
31012002122002021010011
423211030221130001
5200431404420023
65413534104521
7620104506124
oct134514513401
935078067104
1012435232513
115301401270
1224b064b141
131232390962
1485d7543bb
154cba9350d
hex2e5329701

12435232513 has 4 divisors (see below), whose sum is σ = 13565708208. Its totient is φ = 11304756820.

The previous prime is 12435232489. The next prime is 12435232517. The reversal of 12435232513 is 31523253421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31523253421 = 112865750311.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12435232513 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12435232517) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 565237831 + ... + 565237852.

It is an arithmetic number, because the mean of its divisors is an integer number (3391427052).

Almost surely, 212435232513 is an apocalyptic number.

It is an amenable number.

12435232513 is a deficient number, since it is larger than the sum of its proper divisors (1130475695).

12435232513 is a wasteful number, since it uses less digits than its factorization.

12435232513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1130475694.

The product of its digits is 21600, while the sum is 31.

Adding to 12435232513 its reverse (31523253421), we get a palindrome (43958485934).

The spelling of 12435232513 in words is "twelve billion, four hundred thirty-five million, two hundred thirty-two thousand, five hundred thirteen".

Divisors: 1 11 1130475683 12435232513