12440434124233 has 4 divisors (see below), whose sum is σ = 12441073327488. Its totient is φ = 12439794920980.

The previous prime is 12440434124207. The next prime is 12440434124243. The reversal of 12440434124233 is 33242143404421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12440434124233 - 2¹³ = 12440434116041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12440434124192 and 12440434124201.

It is not an unprimeable number, because it can be changed into a prime (12440434124243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 319572433 + ... + 319611358.

It is an arithmetic number, because the mean of its divisors is an integer number (3110268331872).

Almost surely, 2^{12440434124233} is an apocalyptic number.

It is an amenable number.

12440434124233 is a deficient number, since it is larger than the sum of its proper divisors (639203255).

12440434124233 is an equidigital number, since it uses as much as digits as its factorization.

12440434124233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 639203254.

The product of its (nonzero) digits is 221184, while the sum is 37.

Adding to 12440434124233 its reverse (33242143404421), we get a palindrome (45682577528654).

The spelling of 12440434124233 in words is "twelve trillion, four hundred forty billion, four hundred thirty-four million, one hundred twenty-four thousand, two hundred thirty-three".