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12441105553 = 22355789711
BaseRepresentation
bin10111001011000110…
…00011010010010001
31012010001010122102011
423211203003102101
5200434410334203
65414304022521
7620205436522
oct134543032221
935101118364
1012441105553
115304752818
1224b2601a41
131233668c26
14860442849
154cc35376d
hex2e58c3491

12441105553 has 4 divisors (see below), whose sum is σ = 12496895488. Its totient is φ = 12385315620.

The previous prime is 12441105517. The next prime is 12441105629. The reversal of 12441105553 is 35550114421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12441105553 is a prime.

It is a super-2 number, since 2×124411055532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12441105503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27894633 + ... + 27895078.

It is an arithmetic number, because the mean of its divisors is an integer number (3124223872).

Almost surely, 212441105553 is an apocalyptic number.

It is an amenable number.

12441105553 is a deficient number, since it is larger than the sum of its proper divisors (55789935).

12441105553 is an equidigital number, since it uses as much as digits as its factorization.

12441105553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55789934.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 12441105553 its reverse (35550114421), we get a palindrome (47991219974).

The spelling of 12441105553 in words is "twelve billion, four hundred forty-one million, one hundred five thousand, five hundred fifty-three".

Divisors: 1 223 55789711 12441105553