12441303143441 has 4 divisors (see below), whose sum is σ = 12441437639232. Its totient is φ = 12441168647652.

The previous prime is 12441303143413. The next prime is 12441303143527. The reversal of 12441303143441 is 14434130314421.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12441303143441 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12441303143041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67109045 + ... + 67294178.

It is an arithmetic number, because the mean of its divisors is an integer number (3110359409808).

Almost surely, 2^{12441303143441} is an apocalyptic number.

It is an amenable number.

12441303143441 is a deficient number, since it is larger than the sum of its proper divisors (134495791).

12441303143441 is an equidigital number, since it uses as much as digits as its factorization.

12441303143441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 134495790.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 12441303143441 its reverse (14434130314421), we get a palindrome (26875433457862).

The spelling of 12441303143441 in words is "twelve trillion, four hundred forty-one billion, three hundred three million, one hundred forty-three thousand, four hundred forty-one".