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12443020433 = 239217923893
BaseRepresentation
bin10111001011010100…
…10110110010010001
31012010011201221010122
423211222112302101
5200440403123213
65414413040025
7620230633334
oct134552266221
935104657118
1012443020433
115305840468
1224b3186015
131233b896ac
148607c061b
154cc5d0d08
hex2e5a96c91

12443020433 has 8 divisors (see below), whose sum is σ = 12501340800. Its totient is φ = 12384752688.

The previous prime is 12443020397. The next prime is 12443020481. The reversal of 12443020433 is 33402034421.

12443020433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12443020433 - 210 = 12443019409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12443023433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 508835 + ... + 532727.

It is an arithmetic number, because the mean of its divisors is an integer number (1562667600).

Almost surely, 212443020433 is an apocalyptic number.

It is an amenable number.

12443020433 is a deficient number, since it is larger than the sum of its proper divisors (58320367).

12443020433 is a wasteful number, since it uses less digits than its factorization.

12443020433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26311.

The product of its (nonzero) digits is 6912, while the sum is 26.

Adding to 12443020433 its reverse (33402034421), we get a palindrome (45845054854).

The spelling of 12443020433 in words is "twelve billion, four hundred forty-three million, twenty thousand, four hundred thirty-three".

Divisors: 1 239 2179 23893 520781 5710427 52062847 12443020433