Base | Representation |
---|---|
bin | 1011010100010110000011… |
… | …0010100011011000111011 |
3 | 1122001122111210121012010122 |
4 | 2311011200302203120323 |
5 | 3112341101343341103 |
6 | 42244432204003455 |
7 | 2423026330524641 |
oct | 265054062433073 |
9 | 48048453535118 |
10 | 12444144121403 |
11 | 3a68593a35a65 |
12 | 148b91283058b |
13 | 6c3629823107 |
14 | 31042a89b191 |
15 | 168a7a043b38 |
hex | b5160ca363b |
12444144121403 has 4 divisors (see below), whose sum is σ = 12444258437688. Its totient is φ = 12444029805120.
The previous prime is 12444144121349. The next prime is 12444144121471. The reversal of 12444144121403 is 30412144144421.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12444144121403 - 210 = 12444144120379 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12444144121483) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56994701 + ... + 57212622.
It is an arithmetic number, because the mean of its divisors is an integer number (3111064609422).
Almost surely, 212444144121403 is an apocalyptic number.
12444144121403 is a deficient number, since it is larger than the sum of its proper divisors (114316285).
12444144121403 is a wasteful number, since it uses less digits than its factorization.
12444144121403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 114316284.
The product of its (nonzero) digits is 49152, while the sum is 35.
Adding to 12444144121403 its reverse (30412144144421), we get a palindrome (42856288265824).
The spelling of 12444144121403 in words is "twelve trillion, four hundred forty-four billion, one hundred forty-four million, one hundred twenty-one thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •