Base | Representation |
---|---|
bin | 111010000001101011… |
… | …0011011110001000011 |
3 | 102220122022012021221211 |
4 | 1310003112123301003 |
5 | 4020200211423011 |
6 | 133124542230551 |
7 | 12000646524463 |
oct | 1640326336103 |
9 | 386568167854 |
10 | 124610264131 |
11 | 48935277871 |
12 | 20197885457 |
13 | b99b389502 |
14 | 6061755ba3 |
15 | 3394ac4b21 |
hex | 1d0359bc43 |
124610264131 has 4 divisors (see below), whose sum is σ = 124611318000. Its totient is φ = 124609210264.
The previous prime is 124610264123. The next prime is 124610264143. The reversal of 124610264131 is 131462016421.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 124610264131 - 23 = 124610264123 is a prime.
It is a super-2 number, since 2×1246102641312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 124610264093 and 124610264102.
It is not an unprimeable number, because it can be changed into a prime (124610264101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 323356 + ... + 594793.
It is an arithmetic number, because the mean of its divisors is an integer number (31152829500).
Almost surely, 2124610264131 is an apocalyptic number.
124610264131 is a deficient number, since it is larger than the sum of its proper divisors (1053869).
124610264131 is an equidigital number, since it uses as much as digits as its factorization.
124610264131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1053868.
The product of its (nonzero) digits is 6912, while the sum is 31.
The spelling of 124610264131 in words is "one hundred twenty-four billion, six hundred ten million, two hundred sixty-four thousand, one hundred thirty-one".
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