Search a number
-
+
12463106131 = 71780443733
BaseRepresentation
bin10111001101101101…
…11110100001010011
31012011120112101112101
423212312332201103
5201011023344011
65420411341231
7620563440250
oct134666764123
935146471471
1012463106131
11531610a113
1224b9a51817
13123809cb18
1486332c427
154ce24c2c1
hex2e6dbe853

12463106131 has 4 divisors (see below), whose sum is σ = 14243549872. Its totient is φ = 10682662392.

The previous prime is 12463106099. The next prime is 12463106153. The reversal of 12463106131 is 13160136421.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12463106131 - 25 = 12463106099 is a prime.

It is a super-2 number, since 2×124631061312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12463106131.

It is not an unprimeable number, because it can be changed into a prime (12463196131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 890221860 + ... + 890221873.

It is an arithmetic number, because the mean of its divisors is an integer number (3560887468).

Almost surely, 212463106131 is an apocalyptic number.

12463106131 is a deficient number, since it is larger than the sum of its proper divisors (1780443741).

12463106131 is an equidigital number, since it uses as much as digits as its factorization.

12463106131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1780443740.

The product of its (nonzero) digits is 2592, while the sum is 28.

The spelling of 12463106131 in words is "twelve billion, four hundred sixty-three million, one hundred six thousand, one hundred thirty-one".

Divisors: 1 7 1780443733 12463106131