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12501381313257 = 34167127104419
BaseRepresentation
bin1011010111101011010001…
…1001000111001011101001
31122021010020202110210121020
42311322310121013023221
53114310312104011012
642331015535403053
72430123611605254
oct265726431071351
948233222423536
1012501381313257
113a8a895928401
12149aa27383489
136c8b4ba75685
143130da44c09b
1516a2c9e56a8c
hexb5eb46472e9

12501381313257 has 4 divisors (see below), whose sum is σ = 16668508417680. Its totient is φ = 8334254208836.

The previous prime is 12501381313249. The next prime is 12501381313283. The reversal of 12501381313257 is 75231318310521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12501381313257 - 23 = 12501381313249 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12501381313217) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2083563552207 + ... + 2083563552212.

It is an arithmetic number, because the mean of its divisors is an integer number (4167127104420).

Almost surely, 212501381313257 is an apocalyptic number.

It is an amenable number.

12501381313257 is a deficient number, since it is larger than the sum of its proper divisors (4167127104423).

12501381313257 is an equidigital number, since it uses as much as digits as its factorization.

12501381313257 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4167127104422.

The product of its (nonzero) digits is 151200, while the sum is 42.

Adding to 12501381313257 its reverse (75231318310521), we get a palindrome (87732699623778).

The spelling of 12501381313257 in words is "twelve trillion, five hundred one billion, three hundred eighty-one million, three hundred thirteen thousand, two hundred fifty-seven".

Divisors: 1 3 4167127104419 12501381313257