Base | Representation |
---|---|
bin | 1011010111101110110001… |
… | …0111011101011000100011 |
3 | 1122021012200012112112220222 |
4 | 2311323230113131120203 |
5 | 3114314223010412003 |
6 | 42331253043353255 |
7 | 2430156104004203 |
oct | 265735427353043 |
9 | 48235605475828 |
10 | 12502320404003 |
11 | 3a90227a2a161 |
12 | 149b04998282b |
13 | 6c8c6b4a7a81 |
14 | 313189062403 |
15 | 16a332605c38 |
hex | b5eec5dd623 |
12502320404003 has 8 divisors (see below), whose sum is σ = 12557057625600. Its totient is φ = 12447584417088.
The previous prime is 12502320403997. The next prime is 12502320404047. The reversal of 12502320404003 is 30040402320521.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12502320404003 - 216 = 12502320338467 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12502320404083) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24255518 + ... + 24765596.
It is an arithmetic number, because the mean of its divisors is an integer number (1569632203200).
Almost surely, 212502320404003 is an apocalyptic number.
12502320404003 is a deficient number, since it is larger than the sum of its proper divisors (54737221597).
12502320404003 is a wasteful number, since it uses less digits than its factorization.
12502320404003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 617341.
The product of its (nonzero) digits is 5760, while the sum is 26.
Adding to 12502320404003 its reverse (30040402320521), we get a palindrome (42542722724524).
The spelling of 12502320404003 in words is "twelve trillion, five hundred two billion, three hundred twenty million, four hundred four thousand, three".
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