Base | Representation |
---|---|
bin | 11100011011100000001000… |
… | …100010000000101000010001 |
3 | 121101201020210020100011021120 |
4 | 130123200020202000220101 |
5 | 112342034123122214403 |
6 | 1121532220413112453 |
7 | 35223332405026434 |
oct | 3433401042005021 |
9 | 541636706304246 |
10 | 125035231054353 |
11 | 369271642a5314 |
12 | 120347b9a88729 |
13 | 549ca05552a59 |
14 | 22c3a478a981b |
15 | e6c6bed47e53 |
hex | 71b808880a11 |
125035231054353 has 8 divisors (see below), whose sum is σ = 167021799710016. Its totient is φ = 83202741550800.
The previous prime is 125035231054351. The next prime is 125035231054367. The reversal of 125035231054353 is 353450132530521.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 125035231054353 - 21 = 125035231054351 is a prime.
It is not an unprimeable number, because it can be changed into a prime (125035231054351) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38519786133 + ... + 38519789378.
It is an arithmetic number, because the mean of its divisors is an integer number (20877724963752).
Almost surely, 2125035231054353 is an apocalyptic number.
It is an amenable number.
125035231054353 is a deficient number, since it is larger than the sum of its proper divisors (41986568655663).
125035231054353 is an equidigital number, since it uses as much as digits as its factorization.
125035231054353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 77039576055.
The product of its (nonzero) digits is 810000, while the sum is 42.
Adding to 125035231054353 its reverse (353450132530521), we get a palindrome (478485363584874).
The spelling of 125035231054353 in words is "one hundred twenty-five trillion, thirty-five billion, two hundred thirty-one million, fifty-four thousand, three hundred fifty-three".
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