12503814403 has 4 divisors (see below), whose sum is σ = 12808785528. Its totient is φ = 12198843280.

The previous prime is 12503814397. The next prime is 12503814409. The reversal of 12503814403 is 30441830521.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (12503814397) and next prime (12503814409).

It is a cyclic number.

It is not a de Polignac number, because 12503814403 - 2⁵ = 12503814371 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12503814409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152485501 + ... + 152485582.

It is an arithmetic number, because the mean of its divisors is an integer number (3202196382).

Almost surely, 2^12503814403 is an apocalyptic number.

12503814403 is a deficient number, since it is larger than the sum of its proper divisors (304971125).

12503814403 is an equidigital number, since it uses as much as digits as its factorization.

12503814403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 304971124.

The product of its (nonzero) digits is 11520, while the sum is 31.

The spelling of 12503814403 in words is "twelve billion, five hundred three million, eight hundred fourteen thousand, four hundred three".