12511434330001 has 4 divisors (see below), whose sum is σ = 12511557499392. Its totient is φ = 12511311160612.

The previous prime is 12511434329983. The next prime is 12511434330047. The reversal of 12511434330001 is 10003343411521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12511434330001 - 2²⁷ = 12511300112273 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12511434330061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61432201 + ... + 61635526.

It is an arithmetic number, because the mean of its divisors is an integer number (3127889374848).

Almost surely, 2^{12511434330001} is an apocalyptic number.

It is an amenable number.

12511434330001 is a deficient number, since it is larger than the sum of its proper divisors (123169391).

12511434330001 is a wasteful number, since it uses less digits than its factorization.

12511434330001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 123169390.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 12511434330001 its reverse (10003343411521), we get a palindrome (22514777741522).

The spelling of 12511434330001 in words is "twelve trillion, five hundred eleven billion, four hundred thirty-four million, three hundred thirty thousand, one".