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125127075193 = 396313157303
BaseRepresentation
bin111010010001000100…
…1111010010101111001
3102221222022200000110021
41310202021322111321
54022230012401233
6133252123250441
712016523406331
oct1644211722571
9387868600407
10125127075193
114907aa7664a
1220300979a21
13ba51479383
1460b02460c1
1533c515de2d
hex1d2227a579

125127075193 has 4 divisors (see below), whose sum is σ = 125130272128. Its totient is φ = 125123878260.

The previous prime is 125127075187. The next prime is 125127075221. The reversal of 125127075193 is 391570721521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-125127075193 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (125127075173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1539021 + ... + 1618282.

It is an arithmetic number, because the mean of its divisors is an integer number (31282568032).

Almost surely, 2125127075193 is an apocalyptic number.

It is an amenable number.

125127075193 is a deficient number, since it is larger than the sum of its proper divisors (3196935).

125127075193 is an equidigital number, since it uses as much as digits as its factorization.

125127075193 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3196934.

The product of its (nonzero) digits is 132300, while the sum is 43.

The spelling of 125127075193 in words is "one hundred twenty-five billion, one hundred twenty-seven million, seventy-five thousand, one hundred ninety-three".

Divisors: 1 39631 3157303 125127075193