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12513415153 = 42407295079
BaseRepresentation
bin10111010011101101…
…11000111111110001
31012022002012100112111
423221312320333301
5201111413241103
65425405525321
7622044162631
oct135166707761
935262170474
1012513415153
115341551018
122512873841
131245635a85
14869ca66c1
154d388886d
hex2e9db8ff1

12513415153 has 4 divisors (see below), whose sum is σ = 12513752640. Its totient is φ = 12513077668.

The previous prime is 12513415151. The next prime is 12513415157. The reversal of 12513415153 is 35151431521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12513415153 - 21 = 12513415151 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12513415151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105133 + ... + 189946.

It is an arithmetic number, because the mean of its divisors is an integer number (3128438160).

Almost surely, 212513415153 is an apocalyptic number.

It is an amenable number.

12513415153 is a deficient number, since it is larger than the sum of its proper divisors (337487).

12513415153 is an equidigital number, since it uses as much as digits as its factorization.

12513415153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 337486.

The product of its digits is 9000, while the sum is 31.

Adding to 12513415153 its reverse (35151431521), we get a palindrome (47664846674).

The spelling of 12513415153 in words is "twelve billion, five hundred thirteen million, four hundred fifteen thousand, one hundred fifty-three".

Divisors: 1 42407 295079 12513415153