Search a number
-
+
125140000001 = 1011239009901
BaseRepresentation
bin111010010001011101…
…1001101110100000001
3102222000012222122221212
41310202323031310001
54022241320000001
6133253304255505
712020041310102
oct1644273156401
9388005878855
10125140000001
11490872a4205
1220305171595
13ba540532a3
1460b1c4c3a9
1533c63637bb
hex1d22ecdd01

125140000001 has 4 divisors (see below), whose sum is σ = 126379010004. Its totient is φ = 123900990000.

The previous prime is 125139999967. The next prime is 125140000033. The reversal of 125140000001 is 100000041521.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 80543007601 + 44596992400 = 283801^2 + 211180^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-125140000001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (125140000201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 619504850 + ... + 619505051.

It is an arithmetic number, because the mean of its divisors is an integer number (31594752501).

Almost surely, 2125140000001 is an apocalyptic number.

It is an amenable number.

125140000001 is a deficient number, since it is larger than the sum of its proper divisors (1239010003).

125140000001 is a wasteful number, since it uses less digits than its factorization.

125140000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1239010002.

The product of its (nonzero) digits is 40, while the sum is 14.

Adding to 125140000001 its reverse (100000041521), we get a palindrome (225140041522).

The spelling of 125140000001 in words is "one hundred twenty-five billion, one hundred forty million, one", and thus it is an aban number.

Divisors: 1 101 1239009901 125140000001