Search a number
-
+
125144550035 = 5196719661359
BaseRepresentation
bin111010010001100110…
…0100100101010010011
3102222000112112211102122
41310203030210222103
54022244001100120
6133253550004455
712020125060361
oct1644314445223
9388015484378
10125144550035
114908992176a
12203067a672b
13ba54c8730b
1460b26b4631
1533c6961a25
hex1d23324a93

125144550035 has 16 divisors (see below), whose sum is σ = 160436697600. Its totient is φ = 93430773216.

The previous prime is 125144549969. The next prime is 125144550043. The reversal of 125144550035 is 530055441521.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-125144550035 is a prime.

It is a super-2 number, since 2×1251445500352 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 125144549977 and 125144550004.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9824315 + ... + 9837044.

It is an arithmetic number, because the mean of its divisors is an integer number (10027293600).

Almost surely, 2125144550035 is an apocalyptic number.

125144550035 is a deficient number, since it is larger than the sum of its proper divisors (35292147565).

125144550035 is a wasteful number, since it uses less digits than its factorization.

125144550035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19661450.

The product of its (nonzero) digits is 60000, while the sum is 35.

Adding to 125144550035 its reverse (530055441521), we get a palindrome (655199991556).

The spelling of 125144550035 in words is "one hundred twenty-five billion, one hundred forty-four million, five hundred fifty thousand, thirty-five".

Divisors: 1 5 19 67 95 335 1273 6365 19661359 98306795 373565821 1317311053 1867829105 6586555265 25028910007 125144550035