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125146433 = 152382171
BaseRepresentation
bin1110111010110…
…01010101000001
322201111002122002
413131121111001
5224014141213
620230153345
73046504256
oct735312501
9281432562
10125146433
1164707405
1235ab2855
131cc09559
141289942d
15aec0658
hex7759541

125146433 has 4 divisors (see below), whose sum is σ = 125230128. Its totient is φ = 125062740.

The previous prime is 125146363. The next prime is 125146457. The reversal of 125146433 is 334641521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 125146433 - 210 = 125145409 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 125146396 and 125146405.

It is not an unprimeable number, because it can be changed into a prime (125146733) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39563 + ... + 42608.

It is an arithmetic number, because the mean of its divisors is an integer number (31307532).

Almost surely, 2125146433 is an apocalyptic number.

It is an amenable number.

125146433 is a deficient number, since it is larger than the sum of its proper divisors (83695).

125146433 is an equidigital number, since it uses as much as digits as its factorization.

125146433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83694.

The product of its digits is 8640, while the sum is 29.

The square root of 125146433 is about 11186.8866535779. The cubic root of 125146433 is about 500.1951678091.

Adding to 125146433 its reverse (334641521), we get a palindrome (459787954).

The spelling of 125146433 in words is "one hundred twenty-five million, one hundred forty-six thousand, four hundred thirty-three".

Divisors: 1 1523 82171 125146433