Base | Representation |
---|---|
bin | 11100011101001011000100… |
… | …011010101110101110111001 |
3 | 121102010020011022222111110011 |
4 | 130131023010122232232321 |
5 | 112400424301404143340 |
6 | 1122101050153221521 |
7 | 35234535652333252 |
oct | 3435130432565671 |
9 | 542106138874404 |
10 | 125150052412345 |
11 | 36970925a28004 |
12 | 12052b034018a1 |
13 | 54aa7a38917bc |
14 | 22c941b12bb29 |
15 | e7069035b0ea |
hex | 71d2c46aebb9 |
125150052412345 has 16 divisors (see below), whose sum is σ = 153075726236160. Its totient is φ = 98202426562944.
The previous prime is 125150052412339. The next prime is 125150052412351. The reversal of 125150052412345 is 543214250051521.
It is an interprime number because it is at equal distance from previous prime (125150052412339) and next prime (125150052412351).
It is a cyclic number.
It is not a de Polignac number, because 125150052412345 - 217 = 125150052281273 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 125150052412298 and 125150052412307.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 801600585 + ... + 801756694.
It is an arithmetic number, because the mean of its divisors is an integer number (9567232889760).
Almost surely, 2125150052412345 is an apocalyptic number.
It is an amenable number.
125150052412345 is a deficient number, since it is larger than the sum of its proper divisors (27925673823815).
125150052412345 is a wasteful number, since it uses less digits than its factorization.
125150052412345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1603357584.
The product of its (nonzero) digits is 240000, while the sum is 40.
The spelling of 125150052412345 in words is "one hundred twenty-five trillion, one hundred fifty billion, fifty-two million, four hundred twelve thousand, three hundred forty-five".
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