12520113 has 4 divisors (see below), whose sum is σ = 16693488. Its totient is φ = 8346740.

The previous prime is 12520111. The next prime is 12520127. The reversal of 12520113 is 31102521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31102521 = 3 ⋅10367507.

It is a cyclic number.

It is not a de Polignac number, because 12520113 - 2¹ = 12520111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12520092 and 12520101.

It is not an unprimeable number, because it can be changed into a prime (12520111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2086683 + ... + 2086688.

It is an arithmetic number, because the mean of its divisors is an integer number (4173372).

Almost surely, 2^12520113 is an apocalyptic number.

It is an amenable number.

12520113 is a deficient number, since it is larger than the sum of its proper divisors (4173375).

12520113 is an equidigital number, since it uses as much as digits as its factorization.

12520113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4173374.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 12520113 is about 3538.3771703989. The cubic root of 12520113 is about 232.2038500134.

Adding to 12520113 its reverse (31102521), we get a palindrome (43622634).

The spelling of 12520113 in words is "twelve million, five hundred twenty thousand, one hundred thirteen".