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1252103472147 = 31137942529459
BaseRepresentation
bin10010001110000111001…
…011101100010000010011
311102200220020120201221010
4102032013023230100103
5131003301442102042
62355113002502003
7156314201623443
oct22160713542023
94380806521833
101252103472147
11443017849980
121827bab04903
13910c408cab8
144486036a123
152288408159c
hex123872ec413

1252103472147 has 8 divisors (see below), whose sum is σ = 1821241414080. Its totient is φ = 758850589160.

The previous prime is 1252103472143. The next prime is 1252103472161. The reversal of 1252103472147 is 7412743012521.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1252103472147 - 22 = 1252103472143 is a prime.

It is an alternating number because its digits alternate between odd and even.

It is not an unprimeable number, because it can be changed into a prime (1252103472143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18971264697 + ... + 18971264762.

It is an arithmetic number, because the mean of its divisors is an integer number (227655176760).

Almost surely, 21252103472147 is an apocalyptic number.

1252103472147 is a deficient number, since it is larger than the sum of its proper divisors (569137941933).

1252103472147 is a wasteful number, since it uses less digits than its factorization.

1252103472147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37942529473.

The product of its (nonzero) digits is 94080, while the sum is 39.

Adding to 1252103472147 its reverse (7412743012521), we get a palindrome (8664846484668).

The spelling of 1252103472147 in words is "one trillion, two hundred fifty-two billion, one hundred three million, four hundred seventy-two thousand, one hundred forty-seven".