12521685403 has 4 divisors (see below), whose sum is σ = 12530340400. Its totient is φ = 12513030408.

The previous prime is 12521685389. The next prime is 12521685431. The reversal of 12521685403 is 30458612521.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30458612521 = 101 ⋅301570421.

It is a cyclic number.

It is not a de Polignac number, because 12521685403 - 2¹³ = 12521677211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12521685493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4325328 + ... + 4328221.

It is an arithmetic number, because the mean of its divisors is an integer number (3132585100).

Almost surely, 2^12521685403 is an apocalyptic number.

12521685403 is a deficient number, since it is larger than the sum of its proper divisors (8654997).

12521685403 is an equidigital number, since it uses as much as digits as its factorization.

12521685403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8654996.

The product of its (nonzero) digits is 57600, while the sum is 37.

The spelling of 12521685403 in words is "twelve billion, five hundred twenty-one million, six hundred eighty-five thousand, four hundred three".