12523052043233 has 4 divisors (see below), whose sum is σ = 12523127992320. Its totient is φ = 12522976094148.

The previous prime is 12523052043119. The next prime is 12523052043253. The reversal of 12523052043233 is 33234025032521.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12523052043233 - 2¹² = 12523052039137 is a prime.

It is a super-2 number, since 2×12523052043233² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12523052043193 and 12523052043202.

It is not an unprimeable number, because it can be changed into a prime (12523052043253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37726673 + ... + 38057166.

It is an arithmetic number, because the mean of its divisors is an integer number (3130781998080).

Almost surely, 2^{12523052043233} is an apocalyptic number.

It is an amenable number.

12523052043233 is a deficient number, since it is larger than the sum of its proper divisors (75949087).

12523052043233 is an equidigital number, since it uses as much as digits as its factorization.

12523052043233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75949086.

The product of its (nonzero) digits is 129600, while the sum is 35.

Adding to 12523052043233 its reverse (33234025032521), we get a palindrome (45757077075754).

The spelling of 12523052043233 in words is "twelve trillion, five hundred twenty-three billion, fifty-two million, forty-three thousand, two hundred thirty-three".